Bash and batch programming |
| Saturday, 26 March 2005 22:08 | |||
Wanna loop over files in bash and perform a cmd on those files?# (where $i is replaced by the name of the file) for i in ./*.conf; do cmd -c $i; done or using find # (where {} is replaced by the name of the file) find . -name *.conf -exec cmd {} \;I usually opt. for the find version because it seems to be more capable. Then if you are on windows, you don't get find and you can't use the bash syntax of course.... So use, forfiles! What a gem. Gives you access to filename without extension and do things differently if you are testing for files or folders. forfiles is very powerful. O'Reilly -- Ten Essential Windows 2000 Commands Cutting up file/path strings in bashOf course you could use the programs 'dirname' or 'basename'...but you can also do it using bash regex...
Wanna make a CGI script in bash?If you ever need to quickly code up a bash CGI script, use bashlib.Great programming info: Advanced Bash-Scripting Guide Quick syntax guide If if [ expression ] then commands elif [ expression2 ] then commands else commands fiWhile #This program lists the parameters that were passed to the program, along with the parameter number. count=1 while [ -n "$*" ] do echo "This is parameter number $count $1" shift count='expr $count + 1' doneCase statement case $1 in -i) count='grep ^i $2 | wc -l' echo "The number of lines in $2 that start with an i is $count" ;; -e) count='grep ^e $2 | wc -l' echo "The number of lines in $2 that start with an e is $count" ;; *) echo "That option is not recognized" ;; esacFor # In this form, the for statement executes once for each item in the list. # This list can be a variable that contains several words separated by spaces, # or it can be a list of values that is typed directly into the statement. Each # time through the loop, the variable var1 is assigned the current item in the # list, until the last one is reached. for var1 in list do commands doneHow to run a command for each line of a file using sed. sed is your friend. for i in `sed -e 's/,.*$//g' < upgrade/4.1.9-4.1.11/file.lst`; do chmod 666 $i ; done Find and replace using find and sedfind ./ -type f -exec sed -i ’s/string1/string2/’ {} \;
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| Last Updated on Tuesday, 01 December 2009 14:01 |

