Dave Horner's Website - Yet another perspective on things...
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I have discovered a truly marvelous proof of this, which this margin is too narrow to contain.
--
Pierre de Fermat
\begin{bmatrix} 1 & 0 & \ldots & 0 \\
0 & 1 & 0 & \vdots \\
\vdots & 0 & \ddots & 0\\
0 & \ldots & 0 & 1_{n}
\end{bmatrix}